2x^2-56x+192=0

Solution for 2x^2-56x+192=0 equation:

2x^2-56x+192=0

a = 2; b = -56; c = +192;
Δ = b2-4ac
Δ = -562-4·2·192
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-40}{2*2}=\frac{16}{4}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+40}{2*2}=\frac{96}{4}
=24
$